Problem:
Given an array of integers, return indices of the two numbers such that they add up to a specific target.
You may assume that each input would have exactly one solution, and you may not use the same element twice.
Example:
Given nums = [2, 7, 11, 15], target = 9,
Because nums[0] + nums[1] = 2 + 7 = 9,
return [0, 1].
Solution:
class Solution {public:vector<int> twoSum(vector<int>& nums, int target) {vector<int> res(2);int size=nums.size();std::map<int,int> hashMap;for(int i=0;i<size;i++){int curr=target-nums[i];if(hashMap.find(curr)!=hashMap.end()){res[0]=hashMap[curr];res[1]=i;return res;}else{hashMap[nums[i]]=i;}}return res;}};
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